Limits of number sequences online. Remarkable Limits

From the above article, you can find out what the limit is and what it is eaten with - this is VERY important. Why? You may not understand what determinants are and solve them successfully, you may not understand at all what a derivative is and find them on the "five". But if you do not understand what a limit is, then it will be difficult to solve practical tasks. Also, it will not be superfluous to familiarize yourself with the samples of the design of decisions and my recommendations for design. All information is presented in a simple and accessible way.

But for purposes this lesson We will need the following teaching materials: Remarkable Limits And Trigonometric formulas. They can be found on the page. It is best to print the manuals - it is much more convenient, besides, they often have to be accessed offline.

What is remarkable about wonderful limits? The remarkable thing about these limits is that they are proven the greatest minds famous mathematicians, and grateful descendants do not have to suffer terrible limits with a heap trigonometric functions, logarithms, degrees. That is, when finding the limits, we will use ready-made results that have been proven theoretically.

There are several remarkable limits, but in practice, part-time students in 95% of cases have two remarkable limits: First wonderful limit, The second wonderful limit. It should be noted that these are historically established names, and when, for example, they talk about the “first wonderful limit”, they mean by this a very specific thing, and not some random limit taken from the ceiling.

First wonderful limit

Consider the following limit: (instead of native letter"he" I will use the Greek letter "alpha", it is more convenient in terms of presentation of the material).

According to our rule for finding limits (see article Limits. Solution examples) we try to substitute zero into the function: in the numerator we get zero (sine of zero zero), the denominator is obviously also zero. Thus, we are faced with an indeterminacy of the form, which, fortunately, does not need to be disclosed. In the course of mathematical analysis, it is proved that:

This mathematical fact is called First wonderful limit. I will not give an analytical proof of the limit, but here it is geometric sense Let's take a look at the lesson infinitesimal functions.

Often in practical tasks functions can be arranged differently, it doesn't change anything:

– the same first wonderful limit.

But you cannot rearrange the numerator and denominator yourself! If a limit is given in the form , then it must be solved in the same form, without rearranging anything.

In practice, not only a variable can act as a parameter, but also elementary function, complex function. It is only important that it tends to zero.

Examples:
, , ,

Here , , , , and everything is buzzing - the first wonderful limit is applicable.

And here is the next entry - heresy:

Why? Because the polynomial doesn't tend to zero, it tends to five.

By the way, a question for backfilling, why equal limit ? The answer can be found at the end of the lesson.

In practice, not everything is so smooth, almost never a student will be offered to solve a free limit and get an easy credit. Hmmm ... I am writing these lines, and it came to my mind very important thought- still "cheesy" mathematical definitions and it’s better to remember the formulas by heart, this can be of invaluable help in the test, when the issue is decided between “two” and “three”, and the teacher decides to ask the student some simple question or offer to solve the simplest example(“maybe he (a) still knows what ?!”).

Let's move on to practical examples:

Example 1

Find the limit

If we notice a sine in the limit, then this should immediately lead us to think about the possibility of applying the first remarkable limit.

First, we try to substitute 0 in the expression under the limit sign (we do this mentally or on a draft):

So, we have an indeterminacy of the form , its be sure to indicate in making a decision. The expression under the limit sign looks like the first wonderful limit, but this is not quite it, it is under the sine, but in the denominator.

IN similar cases the first wonderful limit we need to organize ourselves, using an artificial device. The line of reasoning can be as follows: “under the sine we have, which means that we also need to get in the denominator”.
And this is done very simply:

That is, the denominator is artificially multiplied in this case by 7 and divided by the same seven. Now the record has taken on a familiar shape.
When the task is drawn up by hand, it is advisable to mark the first wonderful limit with a simple pencil:


What happened? In fact, the circled expression has turned into a unit and disappeared in the product:

Now it only remains to get rid of the three-story fraction:

Who has forgotten the simplification of multi-storey fractions, please refresh the material in the reference book Hot School Mathematics Formulas .

Ready. Final answer:

If you do not want to use pencil marks, then the solution can be formatted like this:



We use the first remarkable limit

Example 2

Find the limit

Again we see a fraction and a sine in the limit. We try to substitute zero in the numerator and denominator:

Indeed, we have uncertainty and, therefore, we need to try to organize the first remarkable limit. On the lesson Limits. Solution examples we considered the rule that when we have uncertainty , then we need to factorize the numerator and denominator into factors. Here - the same thing, we will present the degrees as a product (multipliers):

Similarly to the previous example, we outline with a pencil the wonderful limits (here there are two of them), and indicate that they tend to one:

Actually, the answer is ready:

In the following examples, I will not do art in Paint, I think how to correctly draw up a solution in a notebook - you already understand.

Example 3

Find the limit

We substitute zero in the expression under the limit sign:

An uncertainty has been obtained that needs to be disclosed. If there is a tangent in the limit, then it is almost always converted into sine and cosine according to the well-known trigonometric formula (by the way, they do about the same with cotangent, see below). methodical material Hot trigonometric formulas On the page Mathematical formulas, tables and reference materials).

In this case:

The cosine of zero is equal to one, and it is easy to get rid of it (do not forget to mark that it tends to one):

Thus, if in the limit the cosine is a MULTIPLIER, then, roughly speaking, it must be turned into a unit, which disappears in the product.

Here everything turned out simpler, without any multiplications and divisions. The first remarkable limit also turns into unity and disappears in the product:

As a result, infinity is obtained, it happens.

Example 4

Find the limit

We try to substitute zero in the numerator and denominator:

Uncertainty obtained (cosine of zero, as we remember, is equal to one)

We use trigonometric formula. Take note! For some reason, limits using this formula are very common.

We take out the constant multipliers beyond the limit icon:

Let's organize the first remarkable limit:


Here we have only one wonderful limit, which turns into one and disappears in the product:

Let's get rid of the three-story:

The limit is actually solved, we indicate that the remaining sine tends to zero:

Example 5

Find the limit

This example is more complicated, try to figure it out yourself:

Some limits can be reduced to the 1st remarkable limit by changing the variable, you can read about this a little later in the article Limit Solving Methods.

The second wonderful limit

In the theory of mathematical analysis it is proved that:

This fact is called second remarkable limit.

Reference: is an irrational number.

Not only a variable can act as a parameter, but also a complex function. It is only important that it strives for infinity.

Example 6

Find the limit

When the expression under the limit sign is in the power - this is the first sign that you need to try to apply the second wonderful limit.

But first, as always, we try to substitute endlessly big number into the expression, by what principle this is done, was analyzed in the lesson Limits. Solution examples.

It is easy to see that when the base of the degree, and the exponent - , that is, there is an uncertainty of the form:

This uncertainty is just revealed with the help of the second remarkable limit. But, as often happens, the second wonderful limit does not lie on a silver platter, and it must be artificially organized. You can reason as follows: in this example, the parameter means that we also need to organize in the indicator. To do this, we raise the base to a power, and so that the expression does not change, we raise it to a power:

When the task is drawn up by hand, we mark with a pencil:


Almost everything is ready, the terrible degree has turned into a pretty letter:

At the same time, the limit icon itself is moved to the indicator:

Example 7

Find the limit

Attention! This type of limit is very common, please study this example very carefully.

We try to substitute an infinitely large number in the expression under the limit sign:

The result is an uncertainty. But the second remarkable limit applies to the uncertainty of the form. What to do? You need to convert the base of the degree. We argue like this: in the denominator we have , which means that we also need to organize in the numerator.

constant number but called limit sequences(x n ) if for any arbitrarily small positive numberε > 0 there is a number N such that all values x n, for which n>N, satisfy the inequality

|x n - a|< ε. (6.1)

Write it as follows: or x n → a.

Inequality (6.1) is equivalent to the double inequality

a-ε< x n < a + ε, (6.2)

which means that the points x n, starting from some number n>N, lie inside the interval (a-ε, a + ε ), i.e. fall into any smallε -neighborhood of the point but.

A sequence that has a limit is called converging, otherwise - divergent.

The concept of the limit of a function is a generalization of the concept of the limit of a sequence, since the limit of a sequence can be considered as the limit of the function x n = f(n) of an integer argument n.

Let a function f(x) be given and let a - limit point the domain of definition of this function D(f), i.e. such a point, any neighborhood of which contains points of the set D(f) different from a. Dot a may or may not belong to the set D(f).

Definition 1.The constant number A is called limit functions f(x) at x→a if for any sequence (x n ) of argument values ​​tending to but, the corresponding sequences (f(x n)) have the same limit A.

This definition is called defining the limit of a function according to Heine, or " in the language of sequences”.

Definition 2. The constant number A is called limit functions f(x) at x→a if, by setting an arbitrary arbitrarily small positive number ε , one can find such δ>0 (depending on ε), which for all x lying inε-neighborhoods of a number but, i.e. for x satisfying the inequality
0 <
x-a< ε , the values ​​of the function f(x) will lie inε-neighbourhood of the number A, i.e.|f(x)-A|< ε.

This definition is called defining the limit of a function according to Cauchy, or “in the language ε - δ “.

Definitions 1 and 2 are equivalent. If the function f(x) as x →a has limit equal to A, this is written as

. (6.3)

In the event that the sequence (f(x n)) increases (or decreases) indefinitely for any method of approximation x to your limit but, then we will say that the function f(x) has infinite limit, and write it as:

A variable (i.e. a sequence or function) whose limit is zero is called infinitely small.

A variable whose limit is equal to infinity is called infinitely large.

To find the limit in practice, use the following theorems.

Theorem 1 . If every limit exists

(6.4)

(6.5)

(6.6)

Comment. Expressions like 0/0, ∞/∞, ∞-∞ , 0*∞ , - are uncertain, for example, the ratio of two infinitesimal or infinitely large quantities, and finding a limit of this kind is called “uncertainty disclosure”.

Theorem 2. (6.7)

those. it is possible to pass to the limit at the base of the degree at a constant exponent, in particular, ;

(6.8)

(6.9)

Theorem 3.

(6.10)

(6.11)

where e » 2.7 is the base of the natural logarithm. Formulas (6.10) and (6.11) are called the first wonderful limit and the second remarkable limit.

The corollaries of formula (6.11) are also used in practice:

(6.12)

(6.13)

(6.14)

in particular the limit

If x → a and at the same time x > a, then write x→a + 0. If, in particular, a = 0, then instead of the symbol 0+0 one writes +0. Similarly, if x→a and at the same time x a-0. Numbers and are named accordingly. right limit And left limit functions f(x) at the point but. For the limit of the function f(x) to exist as x→a is necessary and sufficient for . The function f(x) is called continuous at the point x 0 if limit

. (6.15)

Condition (6.15) can be rewritten as:

,

that is, passage to the limit under the sign of a function is possible if it is continuous at a given point.

If equality (6.15) is violated, then we say that at x = xo function f(x) It has gap. Consider the function y = 1/x. The domain of this function is the set R, except for x = 0. The point x = 0 is a limit point of the set D(f), since in any of its neighborhoods, i.e., any open interval containing the point 0 contains points from D(f), but it does not itself belong to this set. The value f(x o)= f(0) is not defined, so the function has a discontinuity at the point x o = 0.

The function f(x) is called continuous on the right at a point x o if limit

,

And continuous on the left at a point x o if limit

Continuity of a function at a point x o is equivalent to its continuity at this point both on the right and on the left.

For a function to be continuous at a point x o, for example, on the right, it is necessary, firstly, that there is a finite limit , and secondly, that this limit be equal to f(x o). Therefore, if at least one of these two conditions is not met, then the function will have a gap.

1. If the limit exists and is not equal to f(x o), then they say that function f(x) at the point xo has break of the first kind, or jump.

2. If the limit is+∞ or -∞ or does not exist, then we say that in point x o the function has a break second kind.

For example, the function y = ctg x at x→ +0 has a limit equal to +∞, hence, at the point x=0 it has a discontinuity of the second kind. Function y = E(x) (integer part of x) at points with integer abscissas has discontinuities of the first kind, or jumps.

A function that is continuous at every point of the interval is called continuous in . A continuous function is represented by a solid curve.

Many problems associated with the continuous growth of some quantity lead to the second remarkable limit. Such tasks, for example, include: the growth of the contribution according to the law of compound interest, the growth of the country's population, the decay of a radioactive substance, the multiplication of bacteria, etc.

Consider example of Ya. I. Perelman, which gives the interpretation of the number e in the compound interest problem. Number e there is a limit . In savings banks, interest money is added to the fixed capital annually. If the connection is made more often, then the capital grows faster, since a large amount is involved in the formation of interest. Let's take a purely theoretical, highly simplified example. Let the bank put 100 den. units at the rate of 100% per annum. If interest-bearing money is added to the fixed capital only after a year, then by this time 100 den. units will turn into 200 den. Now let's see what 100 den will turn into. units, if interest money is added to the fixed capital every six months. After half a year 100 den. units grow up to 100× 1.5 \u003d 150, and after another six months - at 150× 1.5 \u003d 225 (den. units). If the accession is done every 1/3 of the year, then after a year 100 den. units turn into 100× (1 +1/3) 3 » 237 (den. units). We will increase the timeframe for adding interest money to 0.1 year, 0.01 year, 0.001 year, and so on. Then out of 100 den. units a year later:

100 × (1 +1/10) 10 » 259 (den. units),

100 × (1+1/100) 100 » 270 (den. units),

100 × (1+1/1000) 1000 » 271 (den. units).

With an unlimited reduction in the terms of joining interest, the accumulated capital does not grow indefinitely, but approaches a certain limit equal to approximately 271. The capital placed at 100% per annum cannot increase more than 2.71 times, even if the accrued interest were added to the capital every second because the limit

Example 3.1.Using the definition of the limit of a number sequence, prove that the sequence x n =(n-1)/n has a limit equal to 1.

Solution.We need to prove that whateverε > 0 we take, for it there is a natural number N such that for all n N the inequality|xn-1|< ε.

Take any e > 0. Since ; x n -1 =(n+1)/n - 1= 1/n, then to find N it is enough to solve the inequality 1/n< e. Hence n>1/ e and, therefore, N can be taken as the integer part of 1/ e , N = E(1/e ). We thus proved that the limit .

Example 3.2 . Find the limit of a sequence given by a common term .

Solution.Apply the limit sum theorem and find the limit of each term. For n∞ the numerator and denominator of each term tends to infinity, and we cannot directly apply the quotient limit theorem. Therefore, we first transform x n, dividing the numerator and denominator of the first term by n 2, and the second n. Then, applying the quotient limit theorem and the sum limit theorem, we find:

.

Example 3.3. . To find .

Solution. .

Here we have used the degree limit theorem: the limit of a degree is equal to the degree of the limit of the base.

Example 3.4 . To find ( ).

Solution.It is impossible to apply the difference limit theorem, since we have an uncertainty of the form ∞-∞ . Let's transform the formula of the general term:

.

Example 3.5 . Given a function f(x)=2 1/x . Prove that the limit does not exist.

Solution.We use the definition 1 of the limit of a function in terms of a sequence. Take a sequence ( x n ) converging to 0, i.e. Let us show that the value f(x n)= behaves differently for different sequences. Let x n = 1/n. Obviously, then the limit Let's choose now as x n a sequence with a common term x n = -1/n, also tending to zero. Therefore, there is no limit.

Example 3.6 . Prove that the limit does not exist.

Solution.Let x 1 , x 2 ,..., x n ,... be a sequence for which
. How does the sequence (f(x n)) = (sin x n ) behave for different x n → ∞

If x n \u003d p n, then sin x n \u003d sin p n = 0 for all n and limit If
xn=2
p n+ p /2, then sin x n = sin(2 p n+ p /2) = sin p /2 = 1 for all n and hence the limit. Thus does not exist.

Widget for calculating limits on-line

In the top box, instead of sin(x)/x, enter the function whose limit you want to find. In the lower box, enter the number that x tends to and click the Calcular button, get the desired limit. And if you click on Show steps in the upper right corner in the result window, you will get a detailed solution.

Function input rules: sqrt(x) - square root, cbrt(x) - cube root, exp(x) - exponent, ln(x) - natural logarithm, sin(x) - sine, cos(x) - cosine, tan (x) - tangent, cot(x) - cotangent, arcsin(x) - arcsine, arccos(x) - arccosine, arctan(x) - arctangent. Signs: * multiplication, / division, ^ exponentiation, instead of infinity Infinity. Example: the function is entered as sqrt(tan(x/2)).

Function limit- number a will be the limit of some variable value if, in the process of its change, this variable approaches indefinitely a.

Or in other words, the number A is the limit of the function y=f(x) at the point x0, if for any sequence of points from the domain of definition of the function , not equal to x0, and which converges to the point x 0 (lim x n = x0), the sequence of corresponding values ​​of the function converges to the number A.

Graph of a function whose limit with an argument that tends to infinity is L:

Meaning BUT is an limit (limit value) of the function f(x) at the point x0 if for any sequence of points , which converges to x0, but which does not contain x0 as one of its elements (i.e. in the punctured neighborhood x0), the sequence of function values converges to A.

The limit of a function according to Cauchy.

Meaning A will be function limit f(x) at the point x0 if for any forward taken non-negative number ε a non-negative corresponding number will be found δ = δ(ε) such that for each argument x, satisfying the condition 0 < | x - x0 | < δ , the inequality | f(x) A |< ε .

It will be very simple if you understand the essence of the limit and the basic rules for finding it. That the limit of the function f(x) at x aspiring to a equals A, is written like this:

Moreover, the value to which the variable tends x, can be not only a number, but also infinity (∞), sometimes +∞ or -∞, or there may be no limit at all.

To understand how find the limits of a function, it is best to see examples of solutions.

We need to find the limits of the function f(x) = 1/x at:

x→ 2, x→ 0, x∞.

Let's find the solution of the first limit. To do this, you can simply substitute x the number to which it aspires, i.e. 2, we get:

Find the second limit of the function. Here substitute in pure form 0 instead x it is impossible, because cannot be divided by 0. But we can take values ​​close to zero, for example, 0.01; 0.001; 0.0001; 0.00001 and so on, with the value of the function f(x) will increase: 100; 1000; 10000; 100000 and so on. Thus, it can be understood that when x→ 0 the value of the function that is under the limit sign will increase indefinitely, i.e. strive for infinity. Which means:

Regarding the third limit. The same situation as in the previous case, it is impossible to substitute in its purest form. We need to consider the case of unlimited increase x. We alternately substitute 1000; 10000; 100000 and so on, we have that the value of the function f(x) = 1/x will decrease: 0.001; 0.0001; 0.00001; and so on, tending to zero. That's why:

It is necessary to calculate the limit of the function

Starting to solve the second example, we see the uncertainty. From here we find the highest degree of the numerator and denominator - this is x 3, we take it out of brackets in the numerator and denominator and then reduce it by it:

Answer

The first step in finding this limit, substitute the value 1 instead of x, resulting in the uncertainty . To solve it, we decompose the numerator into factors , we will do this by finding the roots of the quadratic equation x 2 + 2x - 3:

D \u003d 2 2 - 4 * 1 * (-3) \u003d 4 +12 \u003d 16 D=√16 = 4

x 1,2 = (-2± 4) / 2x 1 \u003d -3;x2= 1.

So the numerator would be:

Answer

This is the definition of its specific value or a specific area where the function falls, which is limited by the limit.

To decide the limits, follow the rules:

Having understood the essence and main limit decision rules, You'll get basic concept about how to solve them.

Appendix

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Limits give all students of mathematics a lot of trouble. To solve the limit, sometimes you have to use a lot of tricks and choose from a variety of solutions exactly the one that is suitable for a particular example.

In this article, we will not help you understand the limits of your abilities or comprehend the limits of control, but we will try to answer the question: how to understand the limits in higher mathematics? Understanding comes with experience, so at the same time we will give a few detailed examples solution limits with explanations.

The concept of a limit in mathematics

The first question is: what is the limit and the limit of what? We can talk about the limits of numerical sequences and functions. We are interested in the concept of the limit of a function, since it is with them that students most often encounter. But first, the most general definition limit:

Let's say there is some variable. If this value in the process of change indefinitely approaches a certain number a , then a is the limit of this value.

For a function defined in some interval f(x)=y the limit is the number A , to which the function tends when X tending to a certain point but . Dot but belongs to the interval on which the function is defined.

It sounds cumbersome, but it is written very simply:

Lim- from English limit- limit.

There is also a geometric explanation for the definition of the limit, but here we will not go into theory, since we are more interested in the practical than the theoretical side of the issue. When we say that X tends to some value, this means that the variable does not take on the value of a number, but approaches it infinitely close.

Let's bring specific example. The challenge is to find the limit.

To solve this example, we substitute the value x=3 into a function. We get:

By the way, if you are interested, read a separate article on this topic.

In the examples X can tend to any value. It can be any number or infinity. Here is an example when X tends to infinity:

It is intuitively clear that more number in the denominator, the smaller the value will be taken by the function. So, with unlimited growth X meaning 1/x will decrease and approach zero.

As you can see, in order to solve the limit, you just need to substitute the value to strive for into the function X . However, this is the simplest case. Often finding the limit is not so obvious. Within the limits there are uncertainties of type 0/0 or infinity/infinity . What to do in such cases? Use tricks!


Uncertainties within

Uncertainty of the form infinity/infinity

Let there be a limit:

If we try to substitute infinity into the function, we will get infinity both in the numerator and in the denominator. In general, it is worth saying that there is a certain element of art in resolving such uncertainties: one must notice how a function can be transformed in such a way that the uncertainty is gone. In our case, we divide the numerator and denominator by X in senior degree. What will happen?

From the example already considered above, we know that terms containing x in the denominator will tend to zero. Then the solution to the limit is:

To uncover type ambiguities infinity/infinity divide the numerator and denominator by X to the highest degree.


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Another type of uncertainty: 0/0

As always, substitution into the value function x=-1 gives 0 in the numerator and denominator. Look a little more carefully and you will notice that in the numerator we have quadratic equation. Let's find the roots and write:

Let's reduce and get:

So, if you encounter type ambiguity 0/0 - factorize the numerator and denominator.

To make it easier for you to solve examples, here is a table with the limits of some functions:

L'Hopital's rule within

Another powerful way to eliminate both types of uncertainties. What is the essence of the method?

If there is uncertainty in the limit, we take the derivative of the numerator and denominator until the uncertainty disappears.

Visually, L'Hopital's rule looks like this:

Important point : the limit, in which the derivatives of the numerator and denominator are instead of the numerator and denominator, must exist.

And now a real example:

There is a typical uncertainty 0/0 . Take the derivatives of the numerator and denominator:

Voila, the uncertainty is eliminated quickly and elegantly.

We hope that you will be able to put this information to good use in practice and find the answer to the question "how to solve limits in higher mathematics". If you need to calculate the limit of a sequence or the limit of a function at a point, and there is no time for this work from the word “absolutely”, contact a professional student service for a quick and detailed solution.